3.19.37 \(\int \frac {(1-2 x)^{5/2}}{(2+3 x)^4 (3+5 x)} \, dx\)

Optimal. Leaf size=113 \[ \frac {7 (1-2 x)^{3/2}}{9 (3 x+2)^3}+\frac {1073 \sqrt {1-2 x}}{9 (3 x+2)}+\frac {112 \sqrt {1-2 x}}{9 (3 x+2)^2}+\frac {74020 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-242 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \]

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Rubi [A]  time = 0.04, antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {98, 149, 151, 156, 63, 206} \begin {gather*} \frac {7 (1-2 x)^{3/2}}{9 (3 x+2)^3}+\frac {1073 \sqrt {1-2 x}}{9 (3 x+2)}+\frac {112 \sqrt {1-2 x}}{9 (3 x+2)^2}+\frac {74020 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-242 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^(5/2)/((2 + 3*x)^4*(3 + 5*x)),x]

[Out]

(7*(1 - 2*x)^(3/2))/(9*(2 + 3*x)^3) + (112*Sqrt[1 - 2*x])/(9*(2 + 3*x)^2) + (1073*Sqrt[1 - 2*x])/(9*(2 + 3*x))
+ (74020*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(9*Sqrt[21]) - 242*Sqrt[55]*ArcTanh[Sqrt[5/11]*Sqrt[1 - 2*x]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 149

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegerQ[m]

Rule 151

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegerQ[m]

Rule 156

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :>
Dist[(b*g - a*h)/(b*c - a*d), Int[(e + f*x)^p/(a + b*x), x], x] - Dist[(d*g - c*h)/(b*c - a*d), Int[(e + f*x)
^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2}}{(2+3 x)^4 (3+5 x)} \, dx &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {1}{9} \int \frac {(162-93 x) \sqrt {1-2 x}}{(2+3 x)^3 (3+5 x)} \, dx\\ &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {112 \sqrt {1-2 x}}{9 (2+3 x)^2}-\frac {1}{54} \int \frac {-8550+9708 x}{\sqrt {1-2 x} (2+3 x)^2 (3+5 x)} \, dx\\ &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {112 \sqrt {1-2 x}}{9 (2+3 x)^2}+\frac {1073 \sqrt {1-2 x}}{9 (2+3 x)}-\frac {1}{378} \int \frac {-367920+225330 x}{\sqrt {1-2 x} (2+3 x) (3+5 x)} \, dx\\ &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {112 \sqrt {1-2 x}}{9 (2+3 x)^2}+\frac {1073 \sqrt {1-2 x}}{9 (2+3 x)}-\frac {37010}{9} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx+6655 \int \frac {1}{\sqrt {1-2 x} (3+5 x)} \, dx\\ &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {112 \sqrt {1-2 x}}{9 (2+3 x)^2}+\frac {1073 \sqrt {1-2 x}}{9 (2+3 x)}+\frac {37010}{9} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )-6655 \operatorname {Subst}\left (\int \frac {1}{\frac {11}{2}-\frac {5 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=\frac {7 (1-2 x)^{3/2}}{9 (2+3 x)^3}+\frac {112 \sqrt {1-2 x}}{9 (2+3 x)^2}+\frac {1073 \sqrt {1-2 x}}{9 (2+3 x)}+\frac {74020 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-242 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )\\ \end {align*}

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Mathematica [A]  time = 0.13, size = 83, normalized size = 0.73 \begin {gather*} \frac {\sqrt {1-2 x} \left (9657 x^2+13198 x+4523\right )}{9 (3 x+2)^3}+\frac {74020 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-242 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^(5/2)/((2 + 3*x)^4*(3 + 5*x)),x]

[Out]

(Sqrt[1 - 2*x]*(4523 + 13198*x + 9657*x^2))/(9*(2 + 3*x)^3) + (74020*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(9*Sqrt
[21]) - 242*Sqrt[55]*ArcTanh[Sqrt[5/11]*Sqrt[1 - 2*x]]

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IntegrateAlgebraic [A]  time = 0.45, size = 95, normalized size = 0.84 \begin {gather*} -\frac {2 \sqrt {1-2 x} \left (9657 (1-2 x)^2-45710 (1-2 x)+54145\right )}{9 (3 (1-2 x)-7)^3}+\frac {74020 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-242 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 - 2*x)^(5/2)/((2 + 3*x)^4*(3 + 5*x)),x]

[Out]

(-2*(54145 - 45710*(1 - 2*x) + 9657*(1 - 2*x)^2)*Sqrt[1 - 2*x])/(9*(-7 + 3*(1 - 2*x))^3) + (74020*ArcTanh[Sqrt
[3/7]*Sqrt[1 - 2*x]])/(9*Sqrt[21]) - 242*Sqrt[55]*ArcTanh[Sqrt[5/11]*Sqrt[1 - 2*x]]

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fricas [A]  time = 1.44, size = 130, normalized size = 1.15 \begin {gather*} \frac {22869 \, \sqrt {55} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \log \left (\frac {5 \, x + \sqrt {55} \sqrt {-2 \, x + 1} - 8}{5 \, x + 3}\right ) + 37010 \, \sqrt {21} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \log \left (\frac {3 \, x - \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) + 21 \, {\left (9657 \, x^{2} + 13198 \, x + 4523\right )} \sqrt {-2 \, x + 1}}{189 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)^4/(3+5*x),x, algorithm="fricas")

[Out]

1/189*(22869*sqrt(55)*(27*x^3 + 54*x^2 + 36*x + 8)*log((5*x + sqrt(55)*sqrt(-2*x + 1) - 8)/(5*x + 3)) + 37010*
sqrt(21)*(27*x^3 + 54*x^2 + 36*x + 8)*log((3*x - sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2)) + 21*(9657*x^2 + 1319
8*x + 4523)*sqrt(-2*x + 1))/(27*x^3 + 54*x^2 + 36*x + 8)

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giac [A]  time = 1.05, size = 123, normalized size = 1.09 \begin {gather*} 121 \, \sqrt {55} \log \left (\frac {{\left | -2 \, \sqrt {55} + 10 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {37010}{189} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {9657 \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - 45710 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 54145 \, \sqrt {-2 \, x + 1}}{36 \, {\left (3 \, x + 2\right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)^4/(3+5*x),x, algorithm="giac")

[Out]

121*sqrt(55)*log(1/2*abs(-2*sqrt(55) + 10*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) - 37010/189*sqrt(21)*
log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 1/36*(9657*(2*x - 1)^2*sqrt(-2*x
+ 1) - 45710*(-2*x + 1)^(3/2) + 54145*sqrt(-2*x + 1))/(3*x + 2)^3

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maple [A]  time = 0.01, size = 75, normalized size = 0.66 \begin {gather*} \frac {74020 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{189}-242 \sqrt {55}\, \arctanh \left (\frac {\sqrt {55}\, \sqrt {-2 x +1}}{11}\right )-\frac {54 \left (\frac {1073 \left (-2 x +1\right )^{\frac {5}{2}}}{27}-\frac {45710 \left (-2 x +1\right )^{\frac {3}{2}}}{243}+\frac {54145 \sqrt {-2 x +1}}{243}\right )}{\left (-6 x -4\right )^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)/(3*x+2)^4/(5*x+3),x)

[Out]

-242*arctanh(1/11*55^(1/2)*(-2*x+1)^(1/2))*55^(1/2)-54*(1073/27*(-2*x+1)^(5/2)-45710/243*(-2*x+1)^(3/2)+54145/
243*(-2*x+1)^(1/2))/(-6*x-4)^3+74020/189*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.55, size = 128, normalized size = 1.13 \begin {gather*} 121 \, \sqrt {55} \log \left (-\frac {\sqrt {55} - 5 \, \sqrt {-2 \, x + 1}}{\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}}\right ) - \frac {37010}{189} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) + \frac {2 \, {\left (9657 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} - 45710 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 54145 \, \sqrt {-2 \, x + 1}\right )}}{9 \, {\left (27 \, {\left (2 \, x - 1\right )}^{3} + 189 \, {\left (2 \, x - 1\right )}^{2} + 882 \, x - 98\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)^4/(3+5*x),x, algorithm="maxima")

[Out]

121*sqrt(55)*log(-(sqrt(55) - 5*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) - 37010/189*sqrt(21)*log(-(sqrt
(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 2/9*(9657*(-2*x + 1)^(5/2) - 45710*(-2*x + 1)^(3/2)
+ 54145*sqrt(-2*x + 1))/(27*(2*x - 1)^3 + 189*(2*x - 1)^2 + 882*x - 98)

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mupad [B]  time = 0.09, size = 89, normalized size = 0.79 \begin {gather*} \frac {74020\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{189}-242\,\sqrt {55}\,\mathrm {atanh}\left (\frac {\sqrt {55}\,\sqrt {1-2\,x}}{11}\right )+\frac {\frac {108290\,\sqrt {1-2\,x}}{243}-\frac {91420\,{\left (1-2\,x\right )}^{3/2}}{243}+\frac {2146\,{\left (1-2\,x\right )}^{5/2}}{27}}{\frac {98\,x}{3}+7\,{\left (2\,x-1\right )}^2+{\left (2\,x-1\right )}^3-\frac {98}{27}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(5/2)/((3*x + 2)^4*(5*x + 3)),x)

[Out]

(74020*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^(1/2))/7))/189 - 242*55^(1/2)*atanh((55^(1/2)*(1 - 2*x)^(1/2))/11) +
((108290*(1 - 2*x)^(1/2))/243 - (91420*(1 - 2*x)^(3/2))/243 + (2146*(1 - 2*x)^(5/2))/27)/((98*x)/3 + 7*(2*x -
1)^2 + (2*x - 1)^3 - 98/27)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)/(2+3*x)**4/(3+5*x),x)

[Out]

Timed out

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